If you have the gear ratio exactly matched to the peak power vs aerodynamic drag equilibrium point, then you will be able to get to the maximum speed of the given car. This is rarely the case because you have to calculate it and then change things to make it happen. Plus making this happen is not useful for a road car as all of the ratios needed to get it to the top speed will make it a pig to drive normally.
So if your peak power is at 6500 rpm then you work out from that what the equivalent speed is to have equilibrium from aerodynamic drag (yes plus rolling friction etc, but we'll keep it simple because the aero drag is the limiting case eh?). In other words the work being done by the engine is exactly the same as the work required to push through the air at that speed.
Now we make the overall gear ratio in the top have the engine running at exactly 6500 rpm. Drive the car to find out the top speed. Use something other than the speedo to measure it, because the speedo will be wrong.
Obviously for a given torque, more revs equals more power, equals higher top speed. But (echo from Matt

) HORSES FOR COURSES. Shifting the torque band up the rev range by changing cams, heads etc will also increase peak power and for a given Cd and frontal area, will thus increase the top speed.
Someone go and do the experiment and report back on your results.
cheers
michael
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